learn python the hard way 第三版是否不适用于 Python 2.7 版本？
kqij · 2014-05-25 18:28:08 +08:00 · 4384 次点击这是一个创建于 3872 天前的主题，其中的信息可能已经有所发展或是发生改变。
为什么用notepad++运行以下代码时出错，
显示IndentationError: expected an indented block ，
它停留在第三行里，我百度过，听说与空格有关，
百思不得其解，遂请教于诸君。
# this one is like your scripts with argv
def print_two(*args):
arg1 , arg2 = args
print "arg1: %r, arg2: %r" % (arg1, arg2)
# ok, that *args is actually pointless, we can just do this
def print_two_again(arg1, arg2):
print "arg1: %r, arg2: %r" % (arg1, arg2)
# this just takes one argument
def print_one(arg1):
print "arg1: %r" % arg1
# this one takes no arguments
def print_none():
print "I got nothin'."
print_two("Zed","Shaw")
print_two_again("Zed","Shaw")
print_one("First!")
print_none()
显示IndentationError: expected an indented block ，
它停留在第三行里，我百度过，听说与空格有关，
百思不得其解，遂请教于诸君。
# this one is like your scripts with argv
def print_two(*args):
arg1 , arg2 = args
print "arg1: %r, arg2: %r" % (arg1, arg2)
# ok, that *args is actually pointless, we can just do this
def print_two_again(arg1, arg2):
print "arg1: %r, arg2: %r" % (arg1, arg2)
# this just takes one argument
def print_one(arg1):
print "arg1: %r" % arg1
# this one takes no arguments
def print_none():
print "I got nothin'."
print_two("Zed","Shaw")
print_two_again("Zed","Shaw")
print_one("First!")
print_none()
 |
1
Sylv 2014-05-25 18:44:15 +08:00 via iPhone
就是缩进错误，你贴的代码没缩进没法差错
请检查每行的缩进是否正确，有没混用空格和 tab，空格数是不是一致 |
|
2
Sylv 2014-05-25 18:48:03 +08:00 via iPhone  1
估计你是根本就没缩进
缩进是 Python 语法的一部分，请照着书在每行加入合适的缩进，缩进推荐用4个空格 |
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