This topic created in 3805 days ago, the information mentioned may be changed or developed.
4 replies • 2015-12-21 15:50:40 +08:00
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2
adexbn Dec 21, 2015
(´≖◞౪◟≖)
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3
roys Dec 21, 2015
给你一个
'/[\x{1F600}-\x{1F64F}]|[\x{1F300}-\x{1F5FF}]|[\x{1F680}-\x{1F6FF}]|[\x{2600}-\x{26FF}]|[\x{2700}-\x{27BF}]/u';
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