[Sequelize and TypeScript]为什么方法返回值的类型都是 any?

[rabbbit]

代码

!async function() {
  const sequelize = new Sequelize({
    dialect: 'sqlite',
    storage: path.join(process.cwd(), 'test.sqlite'),
    logging: false,
  });
  class Seq extends Model { }
  Seq.init({}, {sequelize, modelName: 'test'});
  await Seq.sync();
  const result = Seq.findAndCountAll({});
}();

F12 点进去看 findAndCountAll 方法有定义返回值的类型, 为什么 result 的类型变成 any 了?

解决了...

https://github.com/sequelize/sequelize/issues/10928